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	<title>Nathaniel Johnston &#187; Papers</title>
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		<title>An Introduction to Schmidt Norms</title>
		<link>http://www.nathanieljohnston.com/2009/10/an-introduction-to-schmidt-norms/</link>
		<comments>http://www.nathanieljohnston.com/2009/10/an-introduction-to-schmidt-norms/#comments</comments>
		<pubDate>Fri, 02 Oct 2009 12:00:58 +0000</pubDate>
		<dc:creator>Nathaniel</dc:creator>
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		<description><![CDATA[In [1], a family of matrix norms (called Schmidt norms) are studied and some of their uses in quantum information theory are explored. The interested reader is of course welcome to read the results presented in that paper, but for the more casual reader I present here one very crucial preliminary, the Schmidt decomposition theorem, [...]]]></description>
			<content:encoded><![CDATA[<p>In [1], a family of matrix norms (called <em>Schmidt norms</em>) are studied and some of their uses in quantum information theory are explored. The interested reader is of course welcome to read the results presented in that paper, but for the more casual reader I present here one very crucial preliminary, the Schmidt decomposition theorem, and a proof that the Schmidt norms actually are (as their name suggests) norms.</p>
<h3>Schmidt Decomposition Theorem</h3>
<p>The <a href="http://en.wikipedia.org/wiki/Schmidt_decomposition">Schmidt decomposition theorem</a> says that any complex vector <strong>v</strong> ∈ <strong>C</strong><sup>n</sup> ⊗ <strong>C</strong><sup>n</sup> can be written as</p>
<p><img class="aligncenter size-full wp-image-737" title="{\bf v}=\sum_{j=1}^k\alpha_j{\bf e_j}\otimes{\bf f_j}" src="http://njohns01home.webfactional.com/wp-content/uploads/2009/09/sch.gif" alt="{\bf v}=\sum_{j=1}^k\alpha_j{\bf e_j}\otimes{\bf f_j}" width="130" height="54" /></p>
<p>where k ≤ n, {α<sub>j</sub>} ⊆ <strong>R</strong> is a family of non-negative real scalars, and {<strong>e</strong><sub>j</sub>}, {<strong>f</strong><sub>j</sub>} ⊆ <strong>C</strong><sup>n</sup> are two orthonormal sets of vectors. I won&#8217;t prove the theorem here &#8212; a proof can be found on its Wikipedia page (it&#8217;s basically the <a href="http://en.wikipedia.org/wiki/Singular_value_decomposition">singular value decomposition</a> in disguise). For our purposes the most important thing to realize is that, for some vectors <strong>v</strong>, we can write <strong>v</strong> in its Schmidt decomposition with k &lt; n. The least k such that <strong>v</strong> can be written in the form above is called the <em>Schmidt rank</em> of <strong>v</strong>, and we denote it by SR(<strong>v</strong>). Every vector <strong>v</strong> has SR(<strong>v</strong>) ≤ n.</p>
<h3>Schmidt Matrix Norms</h3>
<p>The Schmidt k-norm of a matrix X ∈ M<sub>n</sub> is defined to be</p>
<p><img class="aligncenter size-full wp-image-767" title="\big\|X\big\|_{S(k)}:=\sup_{{\bf v},{\bf w}}\big\{|{\bf w}^*X{\bf v}| : \|{\bf v}\|,\|{\bf w}\|\leq 1,SR({\bf v}),SR({\bf w})\leq k\big\}" src="http://njohns01home.webfactional.com/wp-content/uploads/2009/09/sch1.gif" alt="\big\|X\big\|_{S(k)}:=\sup_{{\bf v},{\bf w}}\big\{|{\bf w}^*X{\bf v}| : \|{\bf v}\|,\|{\bf w}\|\leq 1,SR({\bf v}),SR({\bf w})\leq k\big\}" width="477" height="35" /></p>
<p>That might look like a horribly complex definition upon first glance, but it&#8217;s not so hard to get your head around when you realize that the Schmidt k-norm for k = n is simply the standard <a href="http://en.wikipedia.org/wiki/Operator_norm">operator norm</a> of X. It is clear then that the Schmidt k-norm for k &lt; n must be a smaller quantity. Indeed, from a quantum information perspective, the norm measures how much the operator represented by X can stretch pure states that &#8220;aren&#8217;t very entangled.&#8221; The interested reader can learn about the various properties and applications of these norms in [1] &#8212; what I present here is simply a proof that the Schmidt k-norm is indeed a norm (since this is not explicitly done in the paper).</p>
<p><strong>Proof that the Schmidt k-norm is a norm.</strong> It is clear from the definition that the absolute value of a constant pulls out of the Schmidt norms and that the Schmidt norms satisfy the triangle inequality. The only challenging property of the norm to verify is that the Schmidt norm of X being zero implies X = 0.</p>
<p>To prove this, assume that we are in the k = 1 case (if we can show that this property holds for k = 1, it immediately follows that the same property must hold for k &gt; 1). Then recall that we can write X as the sum of elementary tensors, so we can write</p>
<p><img class="aligncenter size-full wp-image-768" title="X=\sum_jA_j\otimes B_j,\ \ {\bf v}={\bf v_1}\otimes{\bf v_2},\text{ and } \ {\bf w}={\bf w_1}\otimes{\bf w_2}." src="http://njohns01home.webfactional.com/wp-content/uploads/2009/09/sch11.gif" alt="X=\sum_jA_j\otimes B_j,\ \ {\bf v}={\bf v_1}\otimes{\bf v_2},\text{ and } \ {\bf w}={\bf w_1}\otimes{\bf w_2}." width="417" height="43" />Furthermore, we may write X in this way using matrices B<sub>j</sub> that are linearly independent (see, for example, Proposition 24 of [2], or simply note that you could choose them to be a family of matrix units). Thus, if the Schmidt 1-norm of X equals zero, then it follows that for any <strong>v</strong><sub><strong>1</strong></sub>, <strong>v</strong><sub><strong>2</strong></sub>, <strong>w</strong><sub><strong>1</strong></sub>, and <strong>w</strong><sub><strong>2</strong></sub>:</p>
<p><img class="aligncenter size-full wp-image-769" title="{\bf w_2}^*\Big(\sum_jc_jB_j\Big){\bf v_2}=0 \ \text{ where }c_j={\bf w_1}^*A_j{\bf v_1} \ \ \forall \, j." src="http://njohns01home.webfactional.com/wp-content/uploads/2009/09/sch2.gif" alt="{\bf w_2}^*\Big(\sum_jc_jB_j\Big){\bf v_2}=0 \ \text{ where }c_j={\bf w_1}^*A_j{\bf v_1} \ \ \forall \, j." width="382" height="46" /></p>
<p>Since this holds for any <strong>v</strong><sub><strong>2</strong></sub> and <strong>w</strong><sub><strong>2</strong></sub>, it follows that</p>
<p><img class="aligncenter size-full wp-image-770" title="\sum_jc_jB_j=0." src="http://njohns01home.webfactional.com/wp-content/uploads/2009/09/sch3.gif" alt="\sum_jc_jB_j=0." width="102" height="43" /></p>
<p>Because we chose the B<sub>j</sub> matrices to be linearly independent, it follows that c<sub>j</sub> = 0 for all j. By referring back to the definition of c<sub>j</sub>, we see that this then implies A<sub>j</sub> = 0 for all j, so X = 0 as desired. QED.</p>
<p><strong>References:</strong></p>
<ol>
<li>N. Johnston and D.W. Kribs, <em><a href="http://www.nathanieljohnston.com/index.php/publications/schmidt-norms-for-quantum-states/">Schmidt norms for quantum states</a></em>. Preprint (2009). <a href="http://arxiv.org/abs/0909.3907">arXiv:0909.3907</a> [quant-ph]</li>
<li>Johnston, N., Kribs, D. W., and Paulsen, V., <em><a href="http://www.nathanieljohnston.com/index.php/publications/computing-stabilized-norms-for-quantum-operations-via-the-theory-of-completely-bounded-maps/">Computing stabilized norms for quantum operations</a></em>. Quantum Information &amp; Computation <strong>9</strong> 1 &amp; 2, 16-35 (2009). <a href="http://arxiv.org/abs/0711.3636">arXiv:0711.3636v1</a> [quant-ph]</li>
</ol>
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		<title>A Brief Introduction to the Multiplicative Domain and its Role in Quantum Error Correction</title>
		<link>http://www.nathanieljohnston.com/2009/07/a-brief-introduction-to-the-multiplicative-domain-and-its-role-in-quantum-error-correction/</link>
		<comments>http://www.nathanieljohnston.com/2009/07/a-brief-introduction-to-the-multiplicative-domain-and-its-role-in-quantum-error-correction/#comments</comments>
		<pubDate>Fri, 24 Jul 2009 04:00:22 +0000</pubDate>
		<dc:creator>Nathaniel</dc:creator>
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		<description><![CDATA[Given a completely positive linear map E: Mn → Mn, its multiplicative domain, denoted MD(E), is an algebra defined as follows: Roughly speaking, MD(E) is the largest subalgebra of Mn on which E behaves multiplicatively. It will be useful to make this notion precise: Definition. Let A be a subalgebra of Mn and let π [...]]]></description>
			<content:encoded><![CDATA[<p>Given a <a href="http://en.wikipedia.org/wiki/Completely_positive_map">completely positive linear map</a> E: M<sub>n</sub> → M<sub>n</sub>, its multiplicative domain, denoted MD(E), is an algebra defined as follows:</p>
<p><img class="aligncenter size-full wp-image-528" title="MD1" src="http://njohns01home.webfactional.com/wp-content/uploads/2009/07/MD11.gif" alt="MD1" width="615" height="25" /></p>
<p>Roughly speaking, MD(E) is the largest subalgebra of M<sub>n</sub> on which E behaves multiplicatively. It will be useful to make this notion precise:</p>
<p style="padding-left: 30px;"><strong>Definition.</strong> Let A be a subalgebra of M<sub>n</sub> and let π : A → M<sub>n</sub>. Then π is said to be a <em>*-homomorphism</em> if π(ab) = π(a)π(b) and π(a<sup>*</sup>) = π(a)<sup>*</sup> for all a,b ∈ A.</p>
<p>Thus, MD(E) is roughly the largest subalgebra of M<sub>n</sub> such that, when E is restricted to it, E is a *-homomorphism (I keep saying &#8220;roughly speaking&#8221; because of the &#8220;∀b ∈ M<sub>n</sub>&#8221; in the definition of MD(E) &#8212; the definition of a *-homomorphism only requires that the multiplicativity hold ∀b ∈ A). Probably the most well-known result about the multiplicative domain is the following theorem of Choi [1,2], which shows how the multiplicative domain simplifies when E is such that E(I) = I (i.e., when E is <em>unital</em>):</p>
<p style="padding-left: 30px; "><strong>Theorem [Choi].</strong> Let E: M<sub>n</sub> → M<sub>n</sub> be a completely positive map such that E(I) = I. Then</p>
<p><img class="aligncenter size-full wp-image-526" title="MD2" src="http://njohns01home.webfactional.com/wp-content/uploads/2009/07/MD2.gif" alt="MD2" width="547" height="22" /></p>
<div id="_mcePaste" style="position: absolute; left: -10000px; top: 0px; width: 1px; height: 1px; overflow-x: hidden; overflow-y: hidden;">Let $\phi : \cl{L}(\cl{H}) \rightarrow \cl{L}(\cl{H})$ be a completely positive, unital map. Then</div>
<div id="_mcePaste" style="position: absolute; left: -10000px; top: 0px; width: 1px; height: 1px; overflow-x: hidden; overflow-y: hidden;">\begin{align*}</div>
<div id="_mcePaste" style="position: absolute; left: -10000px; top: 0px; width: 1px; height: 1px; overflow-x: hidden; overflow-y: hidden;">MD(\phi) = &amp; \big\{ a \in \cl{L}(\cl{H}) : \phi(a)^{*}\phi(a) =</div>
<div id="_mcePaste" style="position: absolute; left: -10000px; top: 0px; width: 1px; height: 1px; overflow-x: hidden; overflow-y: hidden;">\phi(a^*a)\text{ and } \phi(a)\phi(a)^{*} =</div>
<div id="_mcePaste" style="position: absolute; left: -10000px; top: 0px; width: 1px; height: 1px; overflow-x: hidden; overflow-y: hidden;">\phi(aa^*)\big\}.</div>
<div id="_mcePaste" style="position: absolute; left: -10000px; top: 0px; width: 1px; height: 1px; overflow-x: hidden; overflow-y: hidden;">\end{align*}</div>
<p>One thing in particular that this theorem shows is that, when E(I) = I, the multiplicative domain of E only needs to be multiplicative <em>within</em> MD(E) (i.e., we can remove the &#8220;roughly speaking&#8221; that I spoke of earlier).</p>
<h3>MD(E) in Quantum Error Correction</h3>
<p>Before moving onto how MD(E) plays a role in quantum error correction, let&#8217;s consider some examples to get a better feeling for what the multiplicative domain looks like.</p>
<ul>
<li>If E is the identity map (that is, it is the map that takes a matrix to itself) then MD(E) = M<sub>n</sub>, the entire matrix algebra.</li>
<li>If E(a) = Diag(a) (i.e., E simply erases all of the off-diagonal entries of the matrix a), then MD(E) = {Diag(a)}, the set of diagonal matrices.</li>
</ul>
<p>Notice that in the first example, the map E is very well-behaved (as well-behaved as a map ever could be); it preserves all of the information that is put into it. We also see that MD(E) is as large as possible. In the second example, the map E does <em>not</em> preserve information put into it (indeed, one nice way to think about matrices in the quantum information setting is that the diagonal matrices are &#8220;classical&#8221; and rest of the matrices are &#8220;quantum&#8221; &#8212; thus the map E(a) = Diag(a) is effectively removing all of the &#8220;quantumness&#8221; of the input data). We also see that MD(E) is tiny in this case (too small to put any quantum data into).</p>
<p>The above examples then hint that if the map E preserves quantum data, then MD(E) should be large enough to store some quantum information safely. This isn&#8217;t <em>quite</em> true, but the intuition is right, and we get the following result, which was published as Theorem 11 in <a href="http://www.nathanieljohnston.com/index.php/publications/the-multiplicative-domain-in-quantum-error-correction/">this paper</a>:</p>
<p style="padding-left: 30px;"><strong>Theorem.</strong> Let E: M<sub>n</sub> → M<sub>n</sub> be a quantum channel (i.e., a completely positive map such that Tr(E(a)) = Tr(a) for all a ∈ M<sub>n</sub>) such that E(I) = I. Then MD(E) = UCC(E), the algebra of unitarily-correctable codes for E.</p>
<p>What this means is that, when E is unital, its multiplicative domain encodes exactly the matrices that we can correct via a unitary operation. This doesn&#8217;t tell us anything about correctable codes that are not unitarily-correctable, though (i.e., matrices that can only be corrected by a more complicated correction operation). To capture these codes, we have to generalize a bit.</p>
<h3>Generalized Multiplicative Domains</h3>
<p>In order to generalize the multiplicative domain, we can require that the map E be multiplicative with another map π that is already a *-homomorphism, rather than require that it be multiplicative with itself. This is the main theme of <a href="http://www.nathanieljohnston.com/index.php/publications/generalized-multiplicative-domains-and-quantum-error-correction/">this paper</a>, which was submitted for publication this week. We define generalized multiplicative domains as follows:</p>
<p style="padding-left: 30px;"><strong>Definition.</strong> Let A be a subalgebra of M<sub>n</sub>, let E : M<sub>n</sub> → M<sub>n</sub> be completely positive, and let π : A → M<sub>n</sub> be a *-homomorphism. Then the <em>multiplicative domain of E with respect to π</em>, denoted MD<sub>π</sub>(E), is the algebra given by</p>
<p><img class="aligncenter size-full wp-image-530" title="MD3" src="http://njohns01home.webfactional.com/wp-content/uploads/2009/07/MD3.gif" alt="MD3" width="602" height="23" /></p>
<p>It turns out that these generalized multiplicative domains are reasonably well-behaved and generalize the standard multiplicative domain in exactly the way that we wanted: they capture <em>all</em> correctable codes for <em>arbitrary </em>quantum channels (see Theorem 11 of the last paper I mentioned). Furthermore, there are even some characterizations of MD<sub>π</sub>(E) analogous to the theorem of Choi above (see Theorems 5 and 7, as well as Corollary 12).</p>
<p><strong>References:</strong></p>
<ol>
<li>M.-D. Choi, <em>A Schwarz inequality for positive linear maps on C*-algebras.</em> Illinois Journal of Mathematics, <strong>18</strong> (1974), 565-574.</li>
<li>V. I. Paulsen, <em><a href="http://www.amazon.ca/gp/product/0521816696?ie=UTF8&amp;tag=nathjohnshome-20&amp;linkCode=as2&amp;camp=15121&amp;creative=390961&amp;creativeASIN=0521816696">Completely Bounded Maps and Operator Algebras</a>, <span style="font-style: normal;">Cambridge Studies in Advanced Mathematics <strong>78</strong>, Cambridge University Press, Cambridge, 2003.</span></em></li>
</ol>
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